Question

tìm nghiệm (3x-1)(4x+3)/2=(1-3x)(2x-5)

Answer 1

\(\frac{\left(3x-1\right)\left(4x+3\right)}{2}=\left(1-3x\right)\left(2x-5\right)\)

\(\Leftrightarrow\left(3x-1\right)\left(4x+3\right)=\left(1-3x\right)\left(2x-5\right).2\)

\(\Leftrightarrow12x^2+5x-3=12x^2+3x-10\)

\(\Leftrightarrow12x^2+5x+7=-12x^2+34x\)

\(\Leftrightarrow12x^2+5x+7=-12x^2+34x-34x\)

\(\Leftrightarrow12x^2-29x+7=-12x\)

\(\Leftrightarrow12x^2-29x+7=-12x+12x\)

\(\Leftrightarrow24x^2-29x+7=0\)

\(\Rightarrow\hept{\begin{cases}x=\frac{7}{8}\\x=\frac{1}{3}\end{cases}}\)

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