Question

Tìm n thuộc Z sao cho n+4 chia hết cho n+1

Answer 1

n=0;2;-2;-4

Answer 2

n+4 chia hết n+1

ta có: n+4= (n+1)+3

=> n+1+3 chia hết n+1

=> 3 chia hết n+1

=>n+1€Ư(3)={1;3}

=> n+1=1      n+1=3

  n=1-1        n=3-1

   n=0             n=2

vậy n thuộc {0;2}

Answer 3

          \(n+4⋮n+1\)

\(\Rightarrow\left(n+1\right)+3⋮n+1\)

có \(n+1⋮n+1\)

\(\Rightarrow3⋮n+1\)

\(\Rightarrow n+1\inƯ\left(3\right)\) ; \(n\in Z\Rightarrow n+1\in Z\)

\(\Rightarrow n+1\in\left\{-1;-3;1;3\right\}\)

\(\Rightarrow n\in\left\{-2;-4;0;2\right\}\)

Answer 4

Cac ban giai dung roi

Answer 5

Dung roi