\(6n+11⋮3n+2\)
\(2\left(3n+2\right)+7⋮3n+2\)
\(\Rightarrow7⋮3n+2\)
\(\Rightarrow3n+2\inƯ\left(7\right)\)
_" Tự làm nốt - Hoq chắc :)
\(6n+11⋮3n+2\)
\(\Rightarrow2\left(3n+2\right)+7⋮3n+2\)
\(\Rightarrow7⋮3n+2\)
\(\Rightarrow3n+2\in\left\{7;1;-7;-1\right\}\)
\(\Rightarrow3n\in\left\{5;-1;-9;-3\right\}\)
\(\Rightarrow n\in\left\{-3;-1\right\}\) vì \(n\in Z\)
ta có : \(6n+11⋮3n+2\)
\(\Rightarrow2\left(3n+2\right)+7⋮3n+2\)
do : \(2\left(3n+2\right)⋮3n+2\Rightarrow7⋮3n+2\Rightarrow3n+2\inƯ\left(7\right)=\left\{1;-1;7;-7\right\}\)
ta có bảng sau :
| 3n+2 | 1 | -1 | 7 | -7 |
| 3n | -1 | -3 | 5 | -9 |
| n | -1/3 | -1 | 5/3 | -3 |
Vậy n = { -1 ; -3 } thì 6n + 11 chia hết cho 3n + 2
