\(2^m+2^n=2^{m+n}<=>2^m+2^n-2^m-2^n=0\)
\(\Leftrightarrow2^m\left(2^n-1\right)-\left(2^n-1\right)=1<=>\left(2^n-1\right)\left(2^m-1\right)=1\)
\(\Leftrightarrow\int^{2^n-1=1}_{2^m-1=1}=>m=m=1\)
Tim n thuoc N biet (n+1)+(n+2)+...+(n+q)=108 voi q thuoc N*
Tim n thuoc Z biet: n^2-2n+7/n-2
Tim n thuoc N ,biet 2^n = 256
tim m,n thuoc Z biet
\(\frac{m}{2}-\frac{2}{n}=\frac{1}{2}\)
cho A=n+3\n-2 (n thuoc Z)
a) tim n de A la phan so
b) tim n de A thuoc Z
c) tim n biet A=-4
Tim n thuoc Z biet: 3n-2/n+2
tim n thuoc N biet n^2 +3n +7 chia het cho n+2
Tim n thuoc N biet(n^2+13n-13)chia het cho (n+3)
tim n thuoc N biet 2n+5 chia het cho n+2
