\(3n-4⋮n-1\)
\(3n-3-1⋮n-1\)
\(3\left(n-1\right)-1⋮n-1\)
Vì \(3\left(n-1\right)⋮n-1\)
\(\Rightarrow1⋮n-1\)
\(\Rightarrow n-1\inƯ\left(1\right)=\left\{1;-1\right\}\)
\(\Rightarrow n\in\left\{2;0\right\}\)
TA CÓ : 3n-4=3n-3 -1=3*(n-1) -1 . VÌ 3*(n-1) \(⋮n-1\)nên 1\(⋮n-1\Rightarrow n-1\inƯ\left(1\right)\Rightarrow n-1=\left\{-1;1\right\}\)
\(\Rightarrow n=\left\{0;2\right\}\)
2n-3 =2n+2 -5=2*(n+1) -5 \(\Rightarrow n+1\inƯ\left(5\right)\Rightarrow n+1=\left\{-5;-1;1;5\right\}\)
\(\Rightarrow n=\left\{-6;-2;0;4\right\}\)