\(\frac{n-4}{2016}+\frac{n-3}{2015}=\frac{n-2}{2014}+\frac{n-1}{2013}\)
\(\Rightarrow\left(\frac{n-4}{2016}+1\right)+\left(\frac{n-3}{2015}+1\right)=\left(\frac{n-2}{2014}+1\right)+\left(\frac{n-1}{2013}+1\right)\)
\(\Rightarrow\frac{n-4+2016}{2016}+\frac{n-3+2015}{2015}=\frac{n-2+2014}{2014}+\frac{n-1+2013}{2013}\)
\(\Rightarrow\frac{n+2013}{2016}+\frac{n+2013}{2015}=\frac{n+2013}{2014}+\frac{n+2013}{2013}\)
\(\Rightarrow\frac{n+2013}{2016}+\frac{n+2013}{2015}-\frac{n+2013}{2014}-\frac{n+2013}{2013}=0\)
\(\Rightarrow\left(n+2013\right)\left(\frac{1}{2016}+\frac{1}{2015}+\frac{1}{2014}+\frac{1}{2013}\right)=0\)
Mà \(\frac{1}{2016}+\frac{1}{2015}+\frac{1}{2014}+\frac{1}{2013}\ne0\)
=> n + 2013 = 0 => n = -2013
Vậy n = -2013
bạn ơi,cách giải của bạn đúng rồi nhưng n-4+2016=n+2012 , mấy số kia cũng thế chứ ạ
