Ta có : \(\left(-8\right)^3.4^{2n}=\left(-2\right)^{3n}.164\)
\(\Leftrightarrow\frac{2^{4n}}{2^{3n}}=\frac{164}{2^9}\Leftrightarrow2^n=\frac{41}{128}\Leftrightarrow2^{n+7}=41\)
\(\Leftrightarrow n+7=log_2^{41}\Leftrightarrow n=log_2^{41}-7\)
Vậy : ...