Có : n^3-n^2+n-1
= (n^3-n^2)+(n-1)
= (n-1).n^2+(n-1)
= (n-1).(n^2+1)
Để n^3-n^2+n-1 là số nguyên tố
=> n-1=1 hoặc n^2+1=1
=> n=2 hoặc n=0
Thử lại chỉ có n=2 là đúng
Vậy n=2
Tk mk nha
Cho A = n-1/n+4
a,tim n de A la so nguyen to
b,tim n nguyen de A la mot so nguyen
a, tim n de n^2 + 2006 la mot so chinh phuong
b, Cho n la so nguyen to lon hon 3. Hoi n^2 + 2006 la so nguyen to hay hop so.
tim so tu nhien n de (n+3)(n+1) la so nguyen to
Tim so tu nhien n de (n+3)(n+1) la so nguyen to
tim n thuoc N de 2^n-1 va 2^n+1 la so nguyen to
Cho A=n+3/n+2 voi n€z
a)tim dieu kien cua so nguyen n de A la phan so
b)tinh gia tri cua phan so A khi n=1;n=-1
c)tim so nguyen n de phan so A co gia tri la so nguyen
tim n de :2^n-1 va 2^+1 deu la so nguyen to
cho A=n-1/n-4
tim n nguyen de A la mot phan so
tim n nguyen de n la mot so nguyen
Tim n nguyen de p= 10/n^2+4 la so nguyen to chan
