Question

Tim m khi 

\(2-x^2\left(x^2+x+1\right)=-x^4-x^3-x^2+m\)

Answer 1

2-x²(x²+x+1)=-x⁴-x³-x²+m

2-x⁴-x³-x²=-x⁴-x³-x²+m   (=) m=2

vậy ..

chúc bn hc tốt

Answer 2

\(2-x^2\left(x^2+x+1\right)=-x^4-x^3-x^2+m\)

\(\Leftrightarrow-x^4-x^3-x^2-m=-x^4-x^3-x^2+2\)

\(\Leftrightarrow-x^4-x^3-x^2-m+x^4=-x^4-x^3-x^2+2+x^4\)

\(\Leftrightarrow-x^3-x^2-m=-x^3-x^2+2\)

\(\Leftrightarrow-x^3-x^2-m+x^3=-x^3-x^2+2+x^3\)

\(\Leftrightarrow-x^3-m=-x^2+2\)

\(\Leftrightarrow-x^2-m+x^2=-x^2+2+x^2\)

\(\Leftrightarrow-m=2\)

\(\Leftrightarrow\frac{-m}{-1}=\frac{-2}{-1}\)

\(\Leftrightarrow x=2\)

Vậy: x = 2