\(a.m_{ddH_2SO_4}=0,1.500=50\left(g\right)\\ m_{H_2SO_4}=50.9,8\%=4,9\left(g\right)\\ n_{H_2SO_4}=\dfrac{4,9}{98}=0,05\left(mol\right)\\ b.V_{ddMgCl_2}=\dfrac{600}{0,1}=6000\left(ml\right)=6\left(l\right)\\ n_{MgCl_2}=6.0,3=1,8\left(mol\right)\\ m_{MgCl_2}=1,8.95=171\left(g\right)\)
a) \(m_{dd}=0,1.500=50\left(g\right)\)
\(m_{ct}=\dfrac{9,8.50}{100}=4,9\left(g\right)\)
\(n_{H2SO4}=\dfrac{4,9}{98}=0,05\left(mol\right)\)
b) \(V=\dfrac{600}{0,1}=6000\left(ml\right)\)
6000ml = 6l
\(n_{MgCl2}=0,3.6=1,8\left(mol\right)\)
\(m_{MgCl2}=1,8.95=171\left(g\right)\)
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