ban oi bai nay la bai cua de thi vao lop 10 hanoi nam 2018-2019 :
http://kenh14.vn/dap-an-de-thi-mon-toan-tuyen-sinh-vao-lop-10-tai-ha-noi-nam-hoc-2018-2019-20180607165723991.chn
Tìm GTNN của biểu thức sau :
\(\sqrt{\text{x-1}\text{-2}\sqrt{\text{x-2}}}-\sqrt{\text{x+7}\text{-6}\sqrt{\text{x-2}}}\)
giải phương trình:
\(\sqrt{3\text{x}^{2^{ }}-5\text{x}+1}-\sqrt{\text{x}^2-2}=\sqrt{3\left(\text{x}^2-\text{x}-1\right)}-\sqrt{\text{x}^{2^{ }}-3\text{x}+4}\)
Mk đag cần gấp mn giúp mk vs ạ !
Câu 1 Tìm x , biết
a)\(\sqrt{4\text{x}^2+4\text{x}+1}=6\)
b)\(\sqrt{4\text{x}^2-4\sqrt{7}x+7=\sqrt{7}}\)
c\(\sqrt{x^2+2\sqrt{3}x+3}=2\sqrt[]{3}\)
d)\(\sqrt{\left(x-3\right)^2}=9\)
Tìm GTNN và GTLN
\(\sqrt{x\text{+}3}\text{+}\sqrt{5-x}\)
\(choP=\left(\frac{\sqrt{x}+1}{\sqrt{x}}-\frac{2}{\sqrt{x}+1}\right):\left(\frac{\sqrt{x}}{2}+\frac{1}{2\sqrt{x}}\right)a;R\text{ú}tg\text{ọ}nP....b;T\text{í}nhPkhiX=3-2\sqrt{2}c;t\text{ì}mX\text{đ}\text{ể}P=1\)
1) B=\(\left(\frac{\sqrt{x}}{2}\text{+}\frac{1}{2\sqrt{x}}\right)\left(\frac{\sqrt{x}-1}{\sqrt{x}\text{+}1}-\frac{\sqrt{x}\text{+}1}{\sqrt{x}-1}\right)\)
\(P=\frac{2x+2}{\sqrt{x}}+\frac{x\sqrt{x}-1}{x-\sqrt{x}}-\frac{x\sqrt{x}+1}{x+\sqrt{x}}a;r\text{ú}tg\text{ọ}nPb;t\text{ì}mGTNNc\text{ủa}Pc;t\text{í}nhPt\text{ạ}ix=12+6\sqrt{3}\)
Giải phương trình
\(\sqrt{2\text{x}-\sqrt{4\text{x}-1}}-\sqrt{2\text{x}+\sqrt{4\text{x}-1}}=\sqrt{8}\)
B=\(\left(\frac{x\sqrt{x}}{x\text{+}\sqrt{x}\text{+}1}-\frac{1}{x\text{+}\sqrt{x}\text{+}1}\right):\frac{2}{\sqrt{x}\text{+}1}\)
Chứng minh A<0 với mọi 0<x<1
