Ta có: A = 4 - 5x2 - y2 + 2xy - 4x
A = -(5x2 + y2 .- 2xy + 4x - 4)
A = -[(x2 - 2xy + y2) + (4x2 + 4x + 1) - 5]
A = -(x - y)2 - (2x + 1)2 + 5 \(\ge\)5 \(\forall\)x;y
Dấu "=" xảy ra <=> \(\hept{\begin{cases}x-y=0\\2x+1=0\end{cases}}\) => \(x=y=-\frac{1}{2}\)
Vậy MaxA = 5 <=> x = y = -1/2