\(\frac{x-3}{2-x}=\frac{-2}{3}\)
\(3\left(x-3\right)=-2\left(2-x\right)\)
\(3x-9=-4+2x\)
\(3x-2x=-4+9\)
\(x=5\)
Ta có :
\(\frac{x-3}{2-x}=\frac{-2}{3}\)
\(\Rightarrow3\left(x-3\right)=-2\left(2-x\right)\)
\(\Rightarrow3x-9=-4+2x\)
\(\Rightarrow3x-2x=\left(-4\right)+9\)
\(\Rightarrow x=5\)