tim x biet
\(\frac{x+4}{2000}+\frac{x+3}{2001}=\frac{x+2}{2002}+\frac{x+3}{2003}\)
tim x biet :
\(\frac{x+4}{2000}+\frac{x+3}{2001}=\frac{x+2}{2002}+\frac{x+1}{2003}\)
1)tim hai so huu ti x,y biet rang x: y =3 va x-y =25/8
Tim so huu ti x,y biet rang x-y bang x:y va bang 3 lan x+y
tim x \(\frac{x+4}{2000}+\frac{x+3}{2001}=\frac{x+2}{2002}+\frac{x+1}{2003}\)
\(\dfrac{x+4}{2000}+\dfrac{x+3}{2001}=\dfrac{x+2}{2002}+\dfrac{x+1}{2003}\)
x=???
Tìm x biết :
(x+4)/2000 +(x+3)/2001 = (x+2)/2002 +(x+1)/2003
Tìm x, biết:
x+4/2000+x+3/2001=x+2/2002+x+1/2003
tim hai so huu ti x va y(y khac 0) biet rang :
x-y=x.y=x:y