\(A=3x^2-\dfrac{9x}{4}+\dfrac{3}{16x}=\left(3x^2-3x+\dfrac{3}{4}\right)+\left(\dfrac{3}{16x}+\dfrac{3x}{4}\right)-\dfrac{3}{4}\)
\(=3\left(x-\dfrac{1}{2}\right)^2+\left(\dfrac{3}{16x}+\dfrac{3x}{4}\right)-\dfrac{3}{4}\)
\(\ge2\sqrt{\dfrac{3}{16}.\dfrac{3}{4}}-\dfrac{3}{4}=0\)
Vậy GTNN là A = 0 khi \(x=\dfrac{1}{2}\)