Question

tìm giá trị n nguyên dương biết : \(\frac{1}{8}.16^n=2^n\)

 

Answer 1

\(\frac{1}{8}.16^n=2^n\)

Answer 2

\(\frac{1}{8}\).16ⁿ = 2ⁿ

\(\Rightarrow\)\(\frac{1}{8}\)= \(\frac{2^n}{16^n}\)

\(\Rightarrow\)\(\frac{1}{8}\)=  \(\frac{1}{8^n}\)

\(\Rightarrow\)8 = 8ⁿ

\(\Rightarrow\)n = 1

Vậy n=1

Answer 3

\(\frac{1}{8}.16^n=2^n\)

\(\frac{16^n}{8}=2^n\)

\(\frac{2^{4n}}{2^3}=2^n\)

\(2^{4n-3}=2^n\)

\(\Rightarrow4n-3=n\)

\(\Rightarrow4n-n=3\)

\(\Rightarrow3n=3\)

\(\Rightarrow n=1\)

vậy \(n=1\)

Answer 4

\(\frac{1}{8}.16^n=2^n\)

\(\frac{\left(2^4\right)^n}{2^3}=2^n\)

\(2^{4n}-2^3=2^n\)

\(\Rightarrow4n-3=n\)

\(4n-n=3\)

\(3n=3\Rightarrow n=1\)