Ta có: \(|x+\frac{2}{3}|\ge0\forall x\)
\(\Rightarrow-|x+\frac{2}{3}|\le0\forall x\)
\(\Rightarrow2-|x+\frac{2}{3}|\le2-0\forall x\)
Hay \(B\le2\forall x\)
Dấu"=" xảy rá \(\Leftrightarrow x+\frac{2}{3}=0\)
\(\Leftrightarrow x=\frac{-2}{3}\)
Vậy MAX B=2 \(\Leftrightarrow x=\frac{-2}{3}\)
Tim gia tri lon nhat cua
\(B=\frac{4}{4x^2+12x+14}\)
xin loi de bai lan truoc minh danh sai nhe cac ban.Mau giai chi tiet giup minh voi minh dang can gap lam
Cac ban giup minh voi minh can nop gap
Tim gia tri nho nhat cua bieu thuc:
P= / x-1/+/x-2017/+/x-2018/
* Dau gach cheo la dau gia tri tuyet doi nhe
Tim x,y biet
x^2+y^6=0
Minh dang rat gap giup minh voi nhe. Minh cam on!
Bai 5
a)Tim gia tri lon nhat cua A=2016 phan (x-2)2 +(x-y)4+3
b)Tim cac gia tri cua x sao cho A=7-x phan x+2 co gia tri duong
f(x) = 2 (x^3 - x) + x^2 - 3x + 3 - x^3
a) Thu gon hai da thuc tren roi xep theo luy thua giam dan cua bien
b) Tinh f(-1);g (1/2)
c) Tim f(x) + g(x);f(x) - g(x)
d) Tim gia tri cua x de f(x) = g(x) (giup mk voi mk dang can gap)
tim gia tri lon nhat cua R=2013/[(x-2)^2+(x-y)+3]
tim gia tri lon nhat cua A=/x/+5/2/x/+3
Cho tổng: S=a+a^2+a^3+a^4+.....+a^n
(n la so tu nhien, a khac -1. Voi gia tri nao cua n thi S chia het cho a+1)
Minh dang rat gap chieu nay phai nop bai roi giup minh voi nhe!
Minh cam on !
Ban nao lam dung va nhanh nhat minh tick cho
cho bieu thuc A = 2006 -x / 6-x tim gia tri nguyen cua x de A dat gia tri lon nhat. Tim gia tri lon nhat do
