\(B=7-6x-x^2\)
\(B=-\left(x^2+6x-7\right)\)
\(B=-\left(x^2+6x+9-16\right)\)
\(B=-\left(x+3\right)^2+16\le16\)
Max B = 16 \(\Leftrightarrow x=-3\)
B = 7 - 6x - x2
= -( x2 + 6x + 9 ) + 16
= -( x + 3 )2 + 16
-( x + 3 )2 ≤ 0 ∀ x => -( x + 3 )2 + 16 ≤ 16
Đẳng thức xảy ra <=> x + 3 = 0 => x = -3
=> MaxB = 16 <=> x = -3
\(B=7-6x-x^2\)
\(\Rightarrow-B=x^2+6x-7=\left(x+3\right)^2-16\)\(\ge-16\)
\(\Rightarrow B\le16\)
Dấu "=" xảy ra khi \(x=-3\)
