Ta có A = -x2 + 2x + 9 = -x2 + 2x - 1 + 10 = -(x2 - 2x + 1) + 10 = -(x - 1)2 + 10 \(\le\)10
Dấu "=" xảy ra <=> x - 1 = 0
=> x = 1
Vậy Max A = 10 <=> x = 1
Ta có: \(A=-x^2+2x+9\)
\(A=\left(-x^2+2x-1\right)+10\)
\(A=-\left(x^2-2x+1\right)+10\)
\(A=-\left(x-1\right)^2+10\le10\left(\forall x\right)\)
Dấu "=" xảy ra khi: x = 1