Các câu hỏi tương tự
rut gon \(y=\frac{2x+2}{\sqrt{x}}+\frac{x\sqrt{x}-1}{x-\sqrt{x}}-\frac{x^2+\sqrt{x}}{x\sqrt{x}+x}\)
cmr voi moi gia tri cua x de Y co nghia thi bieu thuc \(\frac{7}{y}\)chi nhan moi gia tri nguyen
Cho bieu thuc :
A=\(\frac{\sqrt{x}-1}{\sqrt{x}+1}-\frac{\sqrt{x}+3}{\sqrt{x}-2}-\frac{x+5}{x-\sqrt{x}+2}\)
a.Rut gon A
b.Tim gia tri cua x de A <-1
C.Tìm giá trị của x để A nguyen
cho A = \(\frac{3}{\sqrt{x}-2}\)
tim cac gia tri cua x de A co gia tri nguyen
a\Rut gon bieu thuc
b/Tim gia tri nho nhat cua 4A
A=\(\frac{5\sqrt{x}+4}{x+\sqrt{x}-2}+\frac{\sqrt{x}-1}{\sqrt{x}+2}-\)\(\frac{\sqrt{x}+2}{\sqrt{x}-1}\)
\(M=\left(\frac{\sqrt{x}+2}{x+2\sqrt{x}+1}-\frac{\sqrt{x}-2}{x-1}\right)N=\frac{\sqrt{x}+1}{\sqrt{x}}\) voi x>0 va x khac 1
a) tim gia tri bieu thuc cua N khi x = 25
b) rut gon S = M.N
c) tim m de S<-1
tim x thuoc N de bieu thuc sau co gia tri la so tu nhien: Q=\(\dfrac{\text{x}+1}{\text{x}-\sqrt{\text{x}}+1}\)
Cho bieu thuc P = \(\frac{x-\sqrt{x}}{x+\sqrt{x}+1}\) --\(\frac{2x+\sqrt{x}}{\sqrt{x}}\)+\(\frac{2\left(x-1\right)}{\sqrt{x}-1}\)
a) rut gon P
b) tim x de Q=\(\frac{2\sqrt{x}}{P}\)nhan gia tri nguyen
cho bieu thuc \(P=\left(\frac{\sqrt{x}-2}{x-1}-\frac{\sqrt{x+2}}{x-2\sqrt{x}+1}\right)\cdot\frac{\left(1-x\right)^2}{2}\)
a) rut gon P
b) tim gia tri lon nhat cua P
cho A= \(\frac{1-\sqrt{x}}{1+\sqrt{x}}\) ,B=\((\frac{15-\sqrt{x}}{x-25}\)+\(\frac{2}{\sqrt{x+5}}\)) : \(\frac{\sqrt{x}+1}{\sqrt{x}-5}\)
a) tinh gia tri bieu thuc A khi x = 16
b) rut gon B
c) tim x để ( B-A) nguyen