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mệ quá

tìm giá trị của k để pt sau có 3 nghiệm pb :

\(\left(x-3\right)\left[x^2+\left(k-1\right)x+k^2\right]=0\)

tìm giá trị của k để pt sau có 2 nghiệm pb và cùng âm :

\((x-1)(x^2+kx+k-1)=0\)

Ối giời ối giời ôi
14 tháng 10 2018 lúc 15:07

Bo may la binh day k di hieu ashdbfgbgygygggydfsghuyfhdguuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu3


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