Các câu hỏi tương tự
tinh \(G=\frac{\left(1+\frac{2015}{1}\right)+\left(1+\frac{2015}{2}\right)+...+\left(1+\frac{2015}{1000}\right)}{\left(1+\frac{1000}{1}\right)\left(1+\frac{1000}{2}\right)+....+\left(1+\frac{1000}{2015}\right)}\)
Tính :
\(A=\left(1000-1^3\right).\left(1000-2^3\right).\left(1000-3^3\right).........\left(1000-50^3\right)\)
\(\left(1000-1^{ }3\right).\left(1000-2^{ }3\right).\left(1000-3^{ }3\right)....\left(1000-25^{ }3\right)\)
\(^{\left(-1\right)^2.\left(-1\right)^{ }3.\left(-1\right)^{ }4.......\left(-1\right)^{ }100}\)
B = \(\left(\frac{2017}{1000}\right)^{2017}.\left(\frac{100}{2015}\right)^{2017}:\left(—\frac{2017}{2015.10}\right)^{2017}\).Tính giá trị biểu thức
\(Tính:\left(1000-1^3\right).\left(1000-2^3\right).\left(1000-3^3\right)...\left(1000-50^3\right)\)
tính G=\(\frac{\left(1+\frac{1015}{1}\right)\left(1+\frac{1015}{2}\right)\left(1+\frac{1015}{3}\right)...\left(1+\frac{1015}{1000}\right)}{\left(1+\frac{1000}{1}\right)\left(1+\frac{1000}{2}\right)\left(1+\frac{1000}{3}\right)...\left(1+\frac{1000}{1015}\right)}\)
tính:
a)\(\left(1000-1^3\right).\left(1000-2^3\right).\left(1000-3^3\right).....\left(1000-50^3\right)\)
b)\(\frac{14^{16}.21^{32}.35^{48}}{10^{16}.16^{32}.7^{96}}\)
c)\(D=2009^{\left(1000-1^3\right)\left(1000-2^3\right)...\left(1000-15^3\right)}\)
Giúp mik vớiTính nhanh:a. Aleft(-1right)^{2n}.left(-1right)^n.left(-1right)^{n+1}left(nin Nright)b. Bleft(10000-1^2right)left(10000-2^2right)left(10000-3^2right)..left(10000-1000^2right)c. Cleft(frac{1}{125}-frac{1}{1^3}right)left(frac{1}{125}-frac{1}{2^3}right)left(frac{1}{125}-frac{1}{3^3}right)...left(frac{1}{125}-frac{1}{25^3}right)d. D1999^{left(1000-1^3right)left(1000-2^3right)left(1000-3^3right)...left(1000-10^3right)}
Đọc tiếp
Giúp mik với
Tính nhanh:
a. A=\(\left(-1\right)^{2n}.\left(-1\right)^n.\left(-1\right)^{n+1}\left(n\in N\right)\)
b. B=\(\left(10000-1^2\right)\left(10000-2^2\right)\left(10000-3^2\right)..\left(10000-1000^2\right)\)
c. C=\(\left(\frac{1}{125}-\frac{1}{1^3}\right)\left(\frac{1}{125}-\frac{1}{2^3}\right)\left(\frac{1}{125}-\frac{1}{3^3}\right)...\left(\frac{1}{125}-\frac{1}{25^3}\right)\)
d. D=\(1999^{\left(1000-1^3\right)\left(1000-2^3\right)\left(1000-3^3\right)...\left(1000-10^3\right)}\)
TÍNH
\(\left(1000-1^3\right)\cdot\left(1000-2^3\right)\cdot\left(1000-3^3\right)\cdot\cdot\cdot\left(1000-50^3\right)\)