Ta có :\(33^{33}=33^{4.8+1}=\left(33^4\right)^8.33=...1^8.33=...3\)
=> \(\left(33^{33}\right)^{33}=...3^{33}=...3^{4.8+1}=\left(...1\right)^8.\left(...3\right)\)
=>\(\left(33^{33}\right)^{33}=\left(...1\right).\left(...3\right)=...3\)
Vậy \(\left(33^{33}\right)^{33}\)có tận cùng là 3