1ab x ( 25 + 1 ) = 2000 + 1ab
1ab x 125 + 1ab = 2000 + 1ab
1ab x 125 = 2000
1ab = 2000 : 125 = 160
160 x 125 = 20160
Vậy a = 6
b = 0.
Ta có: 1ab x 126 = 201ab
1ab x (25 + 1) = 2000 + 1ab
1ab x 125 + 1ab = 2000 + 1ab
1ab x 125 = 2000
1ab = 2000 : 125
1ab = 160
160 x 125 = 20160
=> a = 6
=> b = 0
Vậy a = 6
b = 0.