tim x,y biet: \(\frac{1+3y}{12}=\frac{1+5y}{5x}=\frac{1+7y}{4x}\)
\(\frac{1+3y}{12}=\frac{1+5y}{5x}=\frac{1+7y}{4x}\) tim x;y
tim cap so x;y
a, \(\frac{x}{3}\)=\(\frac{y}{7}\)
va xy=84
b,\(\frac{1+3y}{12}\)=\(\frac{1+5y}{5x}=\frac{1+7y}{4x}\)
\(\frac{x-3}{x+5}\)=\(\frac{5}{7}\)
\(\frac{1+3y}{12}=\frac{1+5y}{5x}=\frac{1+7y}{4x}\)
tim so huu ti x
Tìm x;y :\(\frac{1+3y}{12}=\frac{1+5y}{5x}=\frac{1+7y}{4x}\)
Tìm x,y
\(\frac{1+3y}{12}=\frac{1+5y}{5x}=\frac{1+7y}{4x}\)
tìm x, y
\(\frac{1+3y}{12}+\frac{1+5y}{5x}+\frac{1+7y}{4x}\)
Tìm cặp x;y biết: \(\frac{1+3y}{12}=\frac{1+5y}{5x}=\frac{1+7y}{4x}\)
Tìm cặp số (x;y) biết: \(\frac{1+3y}{12}=\frac{1+5y}{5x}=\frac{1+7y}{4x}\)