Ta có:(x+y):(5-z):(y+z):(y+9)=3:1:2:5
=> 5-z=1=>z=4.
y+9=5=>y=-4.
x+y=3=>x-4=3(do y=-4)=>x=7.
Vậy x=7,y=-4,z=4.
Ta có:(x+y):(5-z):(y+z):(y+9)=3:1:2:5
=> 5-z=1=>z=4.
y+9=5=>y=-4.
x+y=3=>x-4=3(do y=-4)=>x=7.
Vậy x=7,y=-4,z=4.
Tim cac so nguyen x,y,z biet
x(x+y+z)=-5
y(x+y+z)=9
z(x+y+z)=5
1. tim cac so x,y,z biet rang 1/2x=2/3y=3/4zva x-y=15
Tim cac so x,y,z biet x/y=9/7; y/2=7/3 va x-y+z=-15
Tim cac so x,y,z biet \(\frac{x}{5}=\frac{y}{7}=\frac{z}{3}\)va x2 va y2 va z2
tim x,y thuoc z biet x/5=y/3=z/4 và x-z=7
tim x,y thuộc z biết x/3=y/4=z/5 và 2z+3y+5z=86
tim cac so x,y,z biet x -1 phan 2 bang y cong 3 phan 4 bang z-5 phan 6 va 5z - 5x - 4y bang 50
Tim x,y,z biet rang: \(\frac{y+z+1}{x}=\frac{x+z+2}{y}=\frac{x+y-3}{z}=\frac{1}{x+y+z}\)
tim x;y thuoc Z
x+1/3=y-z/5=2x+14/9 và x+z =y
Tìm X,Y,Z biet rang X.(X+Y+Z)=-5 ; Y(X+Y+Z)=9 ; Z(X+Y+Z) =5