Có \(\frac{-2}{3}-\frac{5}{12}\)\(< x\le\left(-2\right)^2\)\(-\frac{1}{3}:\frac{1}{6}\)
\(\Rightarrow\frac{-8}{12}-\frac{5}{12}\)\(< x\le\)\(4-\frac{1}{3}.6\)
\(\Rightarrow\frac{-13}{12}< x\le\)\(4-2\)
\(\Rightarrow\frac{-13}{12}< x\le2\)
Vì \(x\in Z\)
\(\Rightarrow x\in\left\{0;1;2\right\}\)