a)2n=32=25
=>n=5
b)3n=32.33.35=310
=>x=10
\(2^n=32\)
\(\Rightarrow2^n=2^5\)
\(\Rightarrow n=5\)
\(3^n=59049\)
\(\Rightarrow3^n=3^{10}\)
\(\Rightarrow n=10\)
tíc mình nha
a/ \(2^n=32\Rightarrow2^n=2^5\Rightarrow n=5\)
b/ \(3^n=9.27.243\Rightarrow3^n=3^2.3^3.3^5\Rightarrow3^n=3^{2+3+5}\Rightarrow n=2+3+5\Rightarrow n=10\)
a, \(2^n=32=2^5\)
b, \(3^n=9.27.243=3^2.3^3.3^5=3^{10}\)