\(\frac{x}{24}=\frac{-2}{3}\Leftrightarrow x=\frac{-2\times24}{3}=-16\)
\(\frac{y}{-18}=\frac{-2}{3}\Leftrightarrow y=\frac{-2\times-18}{3}=12\)
\(\frac{-28}{z}=\frac{-2}{3}\Leftrightarrow z=\frac{-28\times3}{-2}=42\)
\(\frac{-10}{t}=\frac{-2}{3}\Leftrightarrow t=\frac{-10\times3}{-2}=15\)
\(\frac{x}{24}=\frac{y}{-18}=\frac{-28}{z}=\frac{-10}{t}=\frac{-2}{3}\)
\(\Rightarrow t=-15\)
\(\Rightarrow z=42\)
\(\Rightarrow y=12\)
\(\Rightarrow x=-16\)
Ta có \(\frac{x}{24}=\frac{-2}{3}\)
\(\Rightarrow3x=-48\)
\(\Rightarrow x=-16\)
\(\frac{y}{-18}=\frac{-2}{3}\)
\(\Rightarrow3y=36\)
\(\Rightarrow y=12\)
\(\frac{-28}{z}=\frac{-2}{3}\)
\(\Rightarrow-2z=-84\)
\(z=42\)
\(\frac{-10}{t}=\frac{-2}{3}\)
\(\Rightarrow-2t=-30\)
\(\Rightarrow t=15\)