\(1-\frac{10+x}{17+x}=1-\frac{3}{4}\)
\(\frac{7}{17+x}=\frac{1}{4}\)
\(\frac{7}{17+x}=\frac{7}{28}\Rightarrow17+x=28\)
\(x=28-17=11\)
6.(77-x)=7.(40+x) do đó 462-6x=280+7x hay x=14
\(1-\frac{10+x}{17+x}=1-\frac{3}{4}\)
\(\frac{7}{17+x}=\frac{1}{4}\)
\(\frac{7}{17+x}=\frac{7}{28}\Rightarrow17+x=28\)
\(x=28-17=11\)
6.(77-x)=7.(40+x) do đó 462-6x=280+7x hay x=14
Tim cac so nguyen x,y biet
\(\frac{x}{4}=\frac{y}{7}va-y=9\)
Tim cac so nguyen x,y biet
a) \(\frac{x}{4}=\frac{y}{7}\)va \(x-y=9\)
b) \(\frac{x}{2}=\frac{y}{5}\)va 3x - y =5
Tim cac so nguyen x,y biet
a)\(\frac{x}{y}=\frac{2}{5}\)
b)\(\frac{x}{3}=\frac{y}{5}\)
Tim cac so nguyen x,y biet
a)\(\frac{x-3}{y-2}\)=\(\frac{3}{2}\)va x - y = 4
b)\(\frac{x+3}{y-1}\)=\(\frac{3}{4}\)va x + y = 5
Tim cac so nguyen x biet
a)\(\frac{x+2}{3}=\frac{2x-1}{5}\)
b)\(\frac{-x}{4}=\frac{-9}{x}\)
Tim cac so nguyen x,y biet
\(\frac{x-3}{y-2}=\frac{3}{2}\) va x - y = 4
Tim cac so nguyen x,y biet
\(\frac{x+3}{y-1}\) =\(\frac{3}{4}\)va x + y = 5
Tim cac so nguyen x,y biet
\(\frac{x}{6}=\frac{y}{11}\)va 3x - 2y =-20