Ta có : 95\(⋮\)5 ; 2010\(⋮\)5
\(\Rightarrow\)x+6\(⋮\)5
\(\Rightarrow\)12<x+6\(\le\)27
\(\Rightarrow\)x+6\(\in\){15;20;25}
\(\Rightarrow\)x\(\in\){9;14;19}
Vậy x\(\in\){9;14;19}
(Sai thì xin lỗi nha)
\(x+6+95+2010=x+1+5+95+2010=x+1+100+2010=x+1+2110\)
Vì \(2110⋮5\)\(\Rightarrow\)Để \(\left(x+6+95+2010\right)⋮5\)thì \(\left(x+1\right)⋮5\)(1)
Vì \(12< x\le21\)\(\Rightarrow12< x+1\le22\)(2)
Từ (1), (2) \(\Rightarrow x+1\in\left\{15;20\right\}\)\(\Rightarrow x\in\left\{14;19\right\}\)
Vậy \(x\in\left\{14;19\right\}\)
