`Answer:`
`1/5+2/7-1<x<\frac{13}{3}+6/5+\frac{4}{15}`
`VT =1/5+2/7-1=\frac{17}{35}-1=\frac{-18}{35}`
`VP=\frac{13}{3}+6/5+\frac{4}{15}=\frac{83}{15}+\frac{4}{15}=\frac{203}{35}`
`=>\frac{-18}{35}<x<\frac{203}{35}`
`=>-18<x<203`
Vậy `-18<x<203` với `x\inZZ`