\(9a=7b+2c\)(1)
\(9a⋮9\Rightarrow7b+2c=9b-2\left(b-c\right)⋮9\)
\(9b⋮9\Rightarrow2\left(b-c\right)⋮9\Rightarrow b-c⋮9\Rightarrow\left(b-c\right)=\left\{0;9\right\}\)
+ Với \(\left(b-c\right)=0\Rightarrow b=c\) Thay vào (1) \(\Rightarrow9a=7b+2b=9b\Rightarrow a=b\)
\(\Rightarrow a=b=c\)
Với \(\left(b-c\right)=9\Rightarrow b=9;c=0\) Thay vào (1) \(\Rightarrow9a=7.9\Rightarrow a=7\)
Ta có \(\overline{abc}=\left\{790;111;222;....;999\right\}\)