Ta có \(\frac{2n+5}{n+3}=\frac{2\left(n+3\right)-1}{n+3}=-\frac{1}{n+3}\)
\(\Rightarrow n+3\inƯ\left(-1\right)=\left\{\pm1\right\}\)
n + 3 | 1 | -1 |
n | -2 | -4 |
Do \(n\in N\)suy ra ko có giá trị x thỏa mãn
Ta có \(\frac{2n+5}{n+3}=\frac{2\left(n+3\right)-1}{n+3}=-\frac{1}{n+3}\)
\(\Rightarrow n+3\inƯ\left(-1\right)=\left\{\pm1\right\}\)
n + 3 | 1 | -1 |
n | -2 | -4 |
Do \(n\in N\)suy ra ko có giá trị x thỏa mãn
Cho cac bieu thuc
A=n+6 phan n-5 va B=3n-9 phan n-6
a/ Tim gia tri nguyen cua n de A, B la phan so ?
b/ Tim gia tri nguyen cua n de A, B co gia tri nguyen?
c/ Tim gia tri nguyen cua n de A, B co gia tri nguyen lon nhat?
Cho phan so A = n+1/n-3 (nCZ)
a) Tim cac gia tri cua n de A la phan so
b) Tim n de A co gia tri nguyen
tim cac gia tri nguyen cua n de phan so 6n-3 / 3n +1 co gia tri la so nguyen
tim tat ca cac gia tri nguyen cua n de phan so A=3n+2/n-1 co gia tri la so nguyen
Cho A=n+3/n+2 voi n€z
a)tim dieu kien cua so nguyen n de A la phan so
b)tinh gia tri cua phan so A khi n=1;n=-1
c)tim so nguyen n de phan so A co gia tri la so nguyen
tim n thuoc n de cac phan so sau co gia tri nguyen 2n+3/7
bai 1:tim so nguyen x sao cho gia cua cac phan so la so nguyen
a)x+3/x-2
b)x2+3x-2/x+2
chu y:dau / la dau chia trong phan so
bai 2:cho A=2n+1/n-2 voi n la so nguyen
a)tim n de a la phan so
b)tim n de A nguyen
c)tinh gia tri cua A biet:n=2;1;-2;-1
giup minh voi minh dang can.Ai dung minh tick cho
tim cac so nguyen n de cac phan so sau co gia tri la mot so nguyen
n-5/n-3
Tim cac so nguyen de phan so A =n+3 phan n_2nhan gia tri trong tap so nguyen