a, \(\frac{2x-1}{3}+1=\frac{2x-1}{3}-11\)
<=> \(\frac{2x-1}{3}+1-\frac{2x-1}{3}+11=0\)
<=> \(\frac{2x-1-2x-1}{3}+12=0\)
<=> \(\frac{0x-2+36}{3}=0\)
<=> \(0x-2=0\) (Vô lý) => pt vô nghiệm
b, \(\frac{3-2x}{5}\ge0\) <=> \(3-2x\ge0\)
<=> \(x\le\frac{3}{2}\)