\(\frac{ }{abc}\) \(=\frac{ }{ab}\)\(\frac{ }{.ac}\)\(\frac{ }{.7}\)
<=> a.100+b.10+c=(a.10+b).(a.10+c).7
<=> a.100+b.10+c=[(a.10+b).a.10+(a.10+b).c].7
<=> a.100+b.10+c=(a2.100+b.a.10+a.10.c+b.c).7
<=> a.100+b.10+c=[(a2.100+a.10)+(b.a.10+b.c)].7
......