\(\overline{abc}-\overline{ac}=\overline{2cb}+\overline{bc}\)
\(\Rightarrow100a+10b+c-10a-c=200+10c+b+10b+c\)
\(\Rightarrow90a+10b=200+11b+11c\)
\(\Rightarrow90a-200=11c+b\)
Vì \(90a-200>0\Rightarrow90a>200\Rightarrow a>2\)
Ta lại có: \(90a-200=11c+b\Rightarrow11c+b+200=90a\)
\(\Rightarrow11c+b:90\)dư 70
\(\Rightarrow11c+b=90k+70\)
\(\Rightarrow k=0\Rightarrow11c+b=70\)
\(\Rightarrow c=6;b=4\)
\(\Rightarrow70+200=90a\)
\(\Rightarrow90a=270\Rightarrow a=3\Rightarrow\overline{abc}=346\)