Question

Tìm \(a\inℤ\), biết \(\frac{-2}{3}+\frac{1}{4}< \frac{a}{6}< \frac{3}{4}-\frac{1}{3}\)

Answer 1

Ta có\(\frac{-2}{3}\)+\(\frac{1}{4}\)= \(\frac{-8}{12}\)+\(\frac{3}{12}\)= \(\frac{-5}{12}\)

           \(\frac{3}{4}\)-\(\frac{1}{3}\)=\(\frac{9}{12}\)-\(\frac{4}{12}\)=\(\frac{5}{12}\)

=> \(\frac{-5}{12}\)<\(\frac{a}{6}\)<\(\frac{5}{12}\)

=> \(\frac{-5}{12}\)<\(\frac{2a}{12}\)<\(\frac{5}{12}\)

Mà a là số nguyên,2a là số chẵn

=>2a{-4,-2,0,2,4}

=>a{-2,-1,0,1,2}