Ta có \(\hept{\begin{cases}A+B+B+B=89\\A+A+B=63\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}A+3B=89\\2A+B=63\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}2A+6B=178\\2A+B=63\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}5B=115\\2A+B=63\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}B=23\\2A+23=63\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}B=23\\2A=40\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}B=23\\A=20\end{cases}}\)
Vậy \(A+B=20+23=43\)