\(a+a.2+a.3+...+a.49+a.50=12750\)
\(\Leftrightarrow a\left(1+2+3+...+49+50\right)\)
\(\Leftrightarrow1275a=12750\)\
\(\Leftrightarrow a=\frac{12750}{1275}=10\)
Vậy \(a=10\)
\(a+a.2+a.3+...+a.49+a.50=12750\)
\(\Leftrightarrow a\left(1+2+3+...+49+50\right)\)
\(\Leftrightarrow1275a=12750\)\
\(\Leftrightarrow a=\frac{12750}{1275}=10\)
Vậy \(a=10\)
A+a*2+a*3+a*4+...+a*49+a*50=12750.Tìm a
tìm a biết : a+ a* 2+ a*3+a*4+...+ a*49+a*50= 12750
Tìm a biết: a + a × 2 + a × 3 + a × 4 + … + a × 49 + a × 50 = 12750
Tìm a biết : a+a*2+a*3+a*4+....+a*49+a*50=12750
Tìm a biết : a + a * 2 + a * 3 + a * 4 +............+ a * 49 + a * 50 = 12750
Tìm a biết a+a * 2+a*3+a*4....+a*49+a*50=12750
Tìm a biết :a+a*2+a*3+a*4+ ... +a*49+a*50=12750
Tìm a biết: a + a × 2 + a × 3 + a × 4 + … + a × 49 + a × 50 = 12750
Tìm a biết: a + a × 2 + a × 3 + a × 4 + … + a × 49 + a × 50 = 12750