\(f\left(0\right)=-5\)
\(\Rightarrow d=-5\)
\(f\left(1\right)=4\)
\(\Rightarrow a+b+c=9\) (1)
\(f\left(2\right)=31\)
\(\Rightarrow8a+4b+2c=36\) (2)
\(f\left(3\right)=88\)
\(\Rightarrow27a+9b+3c=93\) (3)
\(\left(1\right);\left(2\right);\left(3\right)\Rightarrow\left\{{}\begin{matrix}a=2\\b=3\\c=4\end{matrix}\right.\)
Vậy \(\left(a;b;c;d\right)=\left(2;3;4;-5\right)\)