ta có \(\frac{a-1}{2}=\frac{b-2}{3}=\frac{c-3}{4}\Leftrightarrow\frac{2a-2}{4}=\frac{3b-6}{9}=\frac{c-3}{4}=\frac{2a-2+3b-6-c+3}{4+9-4}\)
\(=\frac{\left(2a+3b-c\right)-\left(2+6-3\right)}{4+9-4}=\frac{50-5}{9}=\frac{45}{9}=5\)
\(\frac{2a-2}{4}=5\Rightarrow a=\frac{4.5+2}{2}=11\)
\(\frac{3b-6}{9}=5\Rightarrow b=\frac{5.9+6}{3}=17\)
\(\frac{c-3}{4}=5\Rightarrow c=5.4+3=23\)