Theo đề bài ta có :
b + c + d + a + c + d + a + b + d + a + b + c = 1 + 2 + 3 + 4
<=> 3a + 3b + 3c + 3d = 10
<=> 3 ( a + b + c + d ) = 10
<=> a + b + c + d = 10/3
=> a = 10/3 - 1 = 7/3
=> b = 10/3 - 2 = 4/3
=> c = 10/3 - 3 = 1/3
=> d = 10/3 - 4 = -2/3
Vậy.........
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b + c + d = 1
a + c + d = 2
a + b + d = 3
a + b + c = 4
=> b + c + d + a + c + d + a + b + d + a + b + c = 1 + 2 + 3 + 4
3b + 3c + 3a + 3d = 10
3( a + b + c + d ) = 10
=> a + b + c + d = 10/3
=> a = 10/3 - 1
a = 7/3
=> b = 10/3 - 2
b = 4/3
=> c = 10/3 - 3
c = 1/3
=> d = 10/3 - 4
d = -2/3
Vậy a = 7/3
b = 4/3
c = 1/3
d = -2/3
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