Theo đề bài ta có:
a + b = -8
b + c = -6
c + a = 16
\(\Rightarrow\)(a + b) + (b + c) + (c + a) = (-8) + (-6) + 16 = 2
Mà (a + b) + (b + c) + (c + a) = a + b + b + c + c + a = 2a + 2b + 2c =2(a+b+c)
\(\Rightarrow a+b+c=2\div2=1\)
\(\Rightarrow a=\left(a+b+c\right)-\left(b+c\right)=1-\left(-6\right)=7\)
\(\Rightarrow b=\left(a+b+c\right)-\left(c+a\right)=1-16=-15\)
\(\Rightarrow c=\left(a+b+c\right)-\left(a+b\right)=1-\left(-8\right)=9\)
Vậy a = 7; b = -15; c = 9
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