Đặt x/2=y/5=k (1)
=>x=2k
y=5k
=>xy=2k*5k=10k^2
=>10=10k^2
=>k^2=1=>k=1
Từ (1)=>x/2=1=>x=2
=>y/5=1=>y=5
Gọi \(\frac{x}{2}=\frac{y}{5}=k\)
\(\Rightarrow x=2k;y=5k\)
\(\Rightarrow x.y=10=2k.5k\)
\(\Rightarrow10=10.k^2\)
\(\Rightarrow k^2=1\)
\(\Rightarrow k=\orbr{\begin{cases}1\\-1\end{cases}}\)
Th1:\(k=1\)
\(\Rightarrow\frac{x}{2}=k\Rightarrow x=1.2=2\)
\(\Rightarrow\frac{y}{5}=1\Rightarrow y=1.5=5\)
Th2:\(k=-1\)
\(\Rightarrow\frac{x}{2}=-1\Rightarrow x=-1.2=-2\)
\(\Rightarrow\frac{y}{5}=-1\Rightarrow y=-1.5=-5\)