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tim hai so tu nhien a va b{a>b} co tong bang 224,biet rang UCLN cua chung bang 28
Tim 2 so TN a va b (a>b) co tich bang 1944, bt rang UCLN cua chung bang 18
Tìm 2 số tn a va bva a>bco yong = 224, biet rang UCLN cua chung =28
tim so tu nhien a va b \(\left(a>b\right)\) co tong bang 224,biet rang uoc chung lon nhat cua no la 28
Biet rang : BCNN(a,b).UCLN(a,b)
a, BCNN cua hai so la 600, UCLN cua chung nho hon 10 lan BCNN. So thu 1 la 120, tim so thu 2.
b, UCLN cua hai so la 12, BCNN cua chung lon gap 6 lan UCLN . So t 1 la 24, tim so t 2
c, Tong cua hai so bang 60, tong giua UCLN va BCNN cua chung la 84. Tim hai so do.
biet rang BCNN(a,b).UCLN(a,b)=a.b
a, tong cua hai so bang 60,tong giua UCLN va BCNN cua chung la 84 tim hai so do
1,tim 2 so tu nhien biet tong chung = 66 UCLN=6 co 1 so chia het cho 5
2,tim 2 so tu nhien biet hieu chung = 84 UCLN = 12
3,tim 2 so tu nhien biet tich = 864 UCLN=6
4,cho 3n+1 va 5n+4 la 2 so nguyen to cung nhau tim UCLN cua 3n+1 va 5n+4
5,cho a=123456789;b=987654321 . Tim UCLN cua a va b
tim so tu nhien a va b \(\left(a>b\right)\) co tong bang 224, biet uoc chung lon nhat cua no la 28
tim so tu nhien a va b \(\left(a>b\right)\) co tong bang 224 , biet uoc chung lon nhat cua no la 28