a.\(2^{100}=\left(2^4\right)^{25}=\left(...6\right)^{25}=...6\) Vậy \(2^{100}\)có tận cùng là 6
b.\(7^{1991}=\left(7^4\right)^{497}+7^3=\left(...1\right)^{497}+...3=...1+...3=...4\)Vậy \(7^{1991}\)có tận cùng là 4
tim 2 chu so tan cung cua 2^100 ; 7^1991
D = 2^1991 TIM CHU SO TAN CUNG
tim chu so tan cung 17!
2*4*6*8*...*98
Tim chu so tan cung
A , 6^2016
B, 9^1991
C , 3^1991
D , 2^1991
tim chu so tan cung cua cac so sau
A=7^2006
B=9^1991
C=2^4+n+2(n thuoc tn
D=127^531
E=3^79+2014^1006
G=8^95.3^314
F=4^256-7^131
nhanh len nhe gap lam rui
Tim 2 chu so tan cung cua 7*2015 (* la so mu nha cac ban)
tim 2 chu so tan cung cua tong: S=7+7^2+7^3+..............+7^4kvoi n thuoc N;k>=1
Tim hai chu so tan cung cua 2100 va 71999
tim chu so tan cung cua 7^2017
tim 2 chu so tan cung cua 2^2003
