Question

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Answer 1

`11+4sqrt6=8+2.2sqrt2.sqrt3+3=(2sqrt2+sqrt3)^2`

`11-4sqrt6=8-2.2sqrt2.sqrt3+3=(2sqrt2-sqrt3)^2`

`13+4sqrt10=8+2.2sqrt2.sqrt5+5=(2sqrt2+sqrt5)^2`

`13-4sqrt10=8-2.2sqrt2.sqrt5+5=(2sqrt2-sqrt5)^2`

Answer 2

\(11+4\sqrt{6}=\left(\sqrt{8}+\sqrt{3}\right)^2\\ 11-4\sqrt{6}=\left(\sqrt{8}-\sqrt{3}\right)^2\\ 13+4\sqrt{10}=\left(\sqrt{8}+\sqrt{5}\right)^2\\ 13-4\sqrt{10}=\left(\sqrt{8}-\sqrt{5}\right)^2\)

Answer 3