Question

Thực hiện phép tính

a) \(2011+5\left[300-\left(17-7\right)^2\right]\) 

b) \(695-\left[200+\left(11-1\right)^2\right]\)

c) \(129-5\left[29-\left(6-1\right)^2\right]\)

d) \(2345-1000:\left[19-2\left(21-18\right)^2\right]\)

Ai làm nhanh mik tick

Answer 1

a) 2011 + 5[300 - (17 - 7)² ]

= 2011 + 5[300 - 100]

= 2011 + 5.200

= 2011 + 1000

= 3011

b) 695 - [200 + (11 - 1)² ]

= 695 - [200 + 100]

= 695 - 300

= 395

c) 129 - 5[29 - (6-1)² ]

= 129 - 5[29 - 25]

= 129 - 5 . 4

= 129 - 20 

= 109

d) 2345 - 1000 : [19 - 2(21-18)² ]

= 2345 - 1000 : [19 - 2 . 9]

= 2345 - 1000 : 1

= 2345 - 1000

= 1345

Answer 2

a, 2011+5 [300-(17-7)² ]  =2011+5[300-10²] 

=2011+5[300-100]=2011+5.200

=2011+1000=3011

b, 695-[200+(11-1)²]=695-[200+10²]

=695-[200+100]=695-300=395