\(4\frac{2}{5}+2\frac{3}{7}-2\frac{2}{5}+5\frac{4}{7}\)
\(=\left(4\frac{2}{5}-2\frac{2}{5}\right)+\left(2\frac{3}{7}+5\frac{4}{7}\right)\)
\(=2+8\)
=10
4 2/5 + 2 3/7 - 2 2/5 + 5 4/7
= 22/5 + 17/7 -12/5 + 39/7
= ( 22/5 - 12/5 ) + ( 17/7 + 39/7 )
= 2 + 8
= 10
\(4\frac{2}{5}+2\frac{3}{7}-2\frac{2}{5}+5\frac{4}{7}\)
=(4+2-2+5)+(\(\frac{2}{5}+\frac{3}{7}-\frac{2}{5}+\frac{4}{7}\))
=\(9+\frac{7}{7}\)
=10
=22/5 +17/7-12/5+39/7
=22/5-12/5+17/7+39/7
=2+8
=10